12 lines
286 B
JavaScript
12 lines
286 B
JavaScript
sum = (...args) => {
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return args.filter(num => num % 2 !== 0).reduce((acc, num) => acc + num, 0);
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}
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sum = (...args) => {
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let total = 0;
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for (let i = 0; i < args.length; i++) {
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if (args[i] % 2 !== 0) {
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total += args[i];
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}
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}
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return total;
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} |